Gives
m1=300g=0.3kg
m2=200g=0.2kg
u1=50cm/sec=0.50cm/sec
u2=100cm/sec=1m/sec
v=?
Momentum conservation
m1u1+m2u2=(m1+m2)v
v=m2+m2m1u1+m2u2
v=0.3+0.20.3×0.50+0.2×1=0.7m/sec (b)
Momentum conservation in elastic collision
m1u1+m2u2=(m1v1+m2v2)
0.3×0.5−0.2×1=0.3v1+0.2v2 0.3v1+0.2v2=0.15−0.2
0.3v1+0.2v2=−0.05→(1)
elastic collision
e=1
v2−v1=u1−u2
v2−v1=0.5+1=1.5→(2)
eqution (1)and(2)
v2=80cm/sec
v1=−70cm/sec
Comments
This is really impressive and helpful, it really helped me with my assignment. Thank you so much.
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