Question #198432

A fire hose ejects a stream of water at an angle of 50.0 above the horizontal. The water behaves like a projectile, what is the highest place on the building the water can reach if the truck is located 30 m away from the building



1
Expert's answer
2021-05-25T16:50:27-0400

Gives

θ=50°\theta=50°

Range=30 meter

We know that

Range

R=u2sin2θgR=\frac{u^2sin2\theta}{g}

Put value

30=u2sin100°9.830=\frac{u^2sin100°}{9.8}

u2=30×9.8sin100°=298.53m/secu^2=\frac{30\times9.8}{sin100°}=298.53m/sec

u=17.28m/secu=17.28m/sec

Maximum highest place building of the water Hmax

H=u2sin2θ2gH=\frac{u^2sin^2\theta}{2g}

Put value


H=17.282sin21002×9.8=15.0mH=\frac{{17.28}^2sin^2100}{2\times9.8}=15.0m


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS