Calculate the standard deviation of these measurements and plot the frequency distribution.
Measurement no.(i) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15. Diameter d (mm) 1.26 1.26 1.29 1.31 1.28 1.27 1.26 1.25 1.28 1.32 1.21 1.27 1.22 1.29 1.28
Mean=1.26+1.26….1.29+1.2815=1.27Mean = \frac{1.26 + 1.26 …. 1.29 + 1.28}{15} = 1.27Mean=151.26+1.26….1.29+1.28=1.27
Standard deviations
σ=115−1((1.26−1.27)2+(1.26−1.27)2+...+(1.29−1.27)2+(1.28−1.27)2)=0.02927σ = \sqrt{\frac{1}{15-1} ((1.26-1.27)^2 + (1.26-1.27)^2 +...+ (1.29-1.27)^2 + (1.28-1.27)^2)} = 0.02927σ=15−11((1.26−1.27)2+(1.26−1.27)2+...+(1.29−1.27)2+(1.28−1.27)2)=0.02927
Frequency distribution
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