Question

with a machine of 65% efficiency if one raises a load of 600n through a distance of 15m applying a force of effort which is equal to 600n calculate the ima(vr) of machine and the distance that an effort moved

Answer 1

$\eta=\frac{M_1}{M_2}=\frac{Pl}{Fs}\implies$ $l=\frac{\eta Fs}{P},$

$l=\frac{0.65\cdot 600\cdot 15}{600}=9.75~m.$