A forklift is used to lift a large 704 kg crate a distance of 5.54 m in 6.12 s. What is the efficiency of the forklift if it takes a total of 8040 J/s of chemical energy in the form of burning fuel to complete this task?
P1=mght=704⋅9.8⋅5.546.12=6250 W,P_1=\frac{mgh}{t}=\frac{704\cdot 9.8\cdot 5.54}{6.12}=6250~W,P1=tmgh=6.12704⋅9.8⋅5.54=6250 W,
η=P1P2=62508040=0.78=78%.\eta=\frac{P_1}{P_2}=\frac{6250}{8040}=0.78=78\%.η=P2P1=80406250=0.78=78%.
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