Answer to Question #178201 in Mechanics | Relativity for SAMUEL

Question

A particle is launched such that it's maximum range is 26.4m. what is the speed at which it is launched?

Answer 1

To be given in question

R_max=26.4 meter

$2\theta=90°$ (maximum range)

To be asked in question

U=?

We know that

$R=\frac{ {u^2}{sin2\theta}}{g}$

$R=\frac{u^2}{g}$

$u^2= Rg$

$u=\sqrt{Rg}$

$g=9.8meter/sec^2$

Put value

$u=\sqrt{26.4\times9.8}$

$u =16.08$ $meter/sec$