A baseball is thrown with a velocity of 31.1 š/š of š = 33.4° above horizontal. What is the horizontal component of the ballās velocity at the highest point of the ballās trajectory?Ā Ā
To beĀ givenĀ inĀ question
"u" =31.1meter/sec
"\\theta=33.4\u00b0"
To beĀ askedĀ inĀ question
Horizontal components of highest point
"u(x)=?"
We knowĀ that
HorizontalĀ componentsĀ of velocity
"u(x)=ucos\\theta"
Put value
=31.1"\\times" "cos" "(33.4\u00b0)"
"u(x)" =25.96meter/sec
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