Question

A baseball is thrown with a velocity of 31.1 𝑚/𝑠 of 𝜃 = 33.4° above horizontal. What is the horizontal component of the ball’s velocity at the highest point of the ball’s trajectory?  

Answer 1

To be given in question

$u$ =31.1meter/sec

$\theta=33.4°$

To be asked in question

Horizontal components of highest point

$u(x)=?$

We know that

Horizontal components of velocity

$u(x)=ucos\theta$

Put value

=31.1$\times$ $cos$ $(33.4°)$

$u(x)$ =25.96meter/sec