Question #170728

You push a shopping cart 200.0 m by exerting a force of 12.00 N onto the handle at an angle of 20o above the horizontal axis. If the cart experiences a force of friction of 2.00 N, calculate the total amount of work done on the cart.


Expert's answer

Let's find the work done by the pushing force:


Wp=Fpdcosθ=12.0 N200.0 mcos20=2255 J.W_p=F_pdcos\theta=12.0\ N\cdot200.0\ m\cdot cos20^{\circ}=2255\ J.

Let's find the work done by the force of friction:


Wfr=Ffrdcosθ=2.0 N200.0 mcos180=400 J.W_{fr}=F_{fr}dcos\theta=2.0\ N\cdot200.0\ m\cdot cos180^{\circ}=-400\ J.

Finally, we can find the net (total) work done on the cart:


Wnet=WpWfr=2255 J400 J=1855 J.W_{net}=W_p-W_{fr}=2255\ J-400\ J=1855\ J.
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