Answer
Given data
u1=24m/s
u1=−12m/s
m1=2kgm2=1kg
Initial momentum
Pi=m1u1+m2u2=48−12=36kg−m/sec.
Velocitu after collosion
v1=m1+m2Pi+em2(u2−u1)
v2=m2+m1Pi+em2(u1−u2)
a)putting all value
e=2/3
v1=2+136+2/3×1(−12−24)=4m/s
v2=2+136+2/3×1(24+12)=16m/s
b) balls stick together
Pi=(m1+m2)v
36=(2+1)v
v=12m/sec
c) perfectly elastic e=1
v1=2+136+2/3(−12−24)=0m/s
v2=2+136+(24+12)=24m/s
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