Answer to Question #165631 in Mechanics | Relativity for Erika

Question

A bus leaves the terminal 208 degrees traveling 65 km turned W at 80 km then 60 degrees for 100 km. How far is the bus from the terminal and in what direction?

Answer 1

x component of distance = $65cos28^{\omicron}+80+100sin60^{\omicron}$

= $224 km$

y component of distance = $-65sin28^{\omicron}+100cos60^{\omicron}$

= $19.48 km$

Resultant = $\sqrt{(224)^2+(19.48)^2}$

= $224.84 km$

Direction: North-West