Question

The position of particle is given as =3-4t+3t²m,what is the instantaneous acceleration at t=2s

Answer 1

Position of particle as function of time is given as

$s(t)=3-4t+3t^2$ m

Differentiating above equation with respect to time,

$\dfrac{ds}{dt}=-4+6t$

Again differentiating the above equation with respect to time,

$\dfrac{d^2s}{dt^2}=6$

$a=6ms^{-2}$

Since acceleration of the particle is independent of time, therefore

instantaneous acceleration at time t=2s will be

$a=6ms^{-2}$