Question #161148

according to an observer on earth,a spaceship is going east with a speed of 0.6c and is going to collide head on in 5s with a comet going west at 0.80c.How fast does the spacecraft see the comet to be approaching.According to their clocks,how much time do they have to get out of the way


Expert's answer

Solution:relativistic speed addition:

S=v+u1+vuc2S=\dfrac{v+u}{1+\frac{vu}{c^2}}



S=0.6c+0.8c1+0.60.8=1.4c1.48=0.946cS=\dfrac{\frac{0.6}{c}+\frac{0.8}{c}}{1+0.6*0.8}=\dfrac{\frac{1.4}{c}}{1.48}=0.946c



time dilation:

t=1γγ=1(1(V2c2))t'=\dfrac{1}{γγ}=\dfrac{1}{\sqrt{\smash[b]{(1-(\frac{V^2}{c^2}))}}}


γ=1(1(0.9462))=3.08γ=\dfrac{1}{\sqrt{\smash[b]{(1-(0.946^2))}}}=3.08



t=53.08=1.62st'=\dfrac{5}{3.08}=1.62s



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