A nail is fired into a block of wood at a velocity of 200 m/s. If the deceleration is 2 million m/s2 how far does the nail travel before it comes to a stop?
Assuming that deceleration keeps constant during the braking process, we can use one of the kinematics equations, as follows:
"v^2_f-v^2_o=2*a*(\\Delta x)"
where "v_f" is the final velocity (0 in our case), "v_o" is the initial velocity (200 "\\tfrac{m}{s}" ), decceleration (-2000000 "\\tfrac{m}{s^2}" ), and Δx is the distance traveled.
"\\dfrac{}{}"
"\\Delta x=\\dfrac{-v^2_o}{2*a}=\\dfrac{-(200)^2}{2(-2000000)}"
"\\Delta x=0.01\\;m=1cm"
That's a lot of deceleration! The nail would travel 1 cm.
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