Question #153520

The viscous drag force F, on a sphere of radius r, moving through a fluid with velocity v, can be expressed as F = 6PLrv, where L is the coefficient of viscosity of the fluid and P = pie(22/7). What are the base units of L?


1
Expert's answer
2021-01-10T18:30:35-0500

Explanation & Calculations


  • Dimensional analysis is the method practiced in these types of questions.
  • Therefore,

[F]=[6πLrv]=[6π][L][r][v]MLT2=[L]×L×LT1[L]=MLT2L2T1[L]=ML1T1\qquad\qquad \begin{aligned} \small [F]&=\small [6\pi Lrv]=[6\pi][L][r][v]\\ \small MLT^{-2}&= \small [L]\times L\times LT^{-1}\\ \small [L]&=\small \frac{MLT^{-2}}{L^2T^{-1}}\\ \small [L]&= \small ML^{-1}T^{-1} \end{aligned}

  • Considering the corresponding units yeild

Units of L=kgm1s1\qquad\qquad \begin{aligned} \small \text{Units of L}&= \small \bold{kgm^{-1}s^{-1}} \end{aligned}


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