Explanations & Calculations
- Assume the mass is hung by the chain of 13m & pulled perpendicularly.
- Considering the equilibrium of the system at a distance of 5m from the starting point, the force needed can be calculated.
- In the beginning, the needed force is zero as there is no force acting opposite to what we apply, and gradually a component of its own weight starts acting as an opposite force to what we apply as it moves in a circular arch from the start to the final position.
Applying Newton's second for the verticle equilibrium ↑ ,
Tsinθ−mgTsinθ=0=60kg×9.8=588N⋯(1)
From the horizontal equilibrium,
Tcosθ=F⋯(2)
tanθF=F588=tanθ588
- By simple geometry at the equilibrium position, tanθ can be found. Chain is 13m, horizontal is 5m hence the verticle side 12m (by pythagoras's)
- Thereofre,
F=512588=245N
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