Answer to Question #152946 in Mechanics | Relativity for Alan

Question

A carnot engine operates between two reserviour at temperature T1 and T3 . The workout put of the engine is 0.6 times the heart rejected. The difference in temperature between the source and sink is 200k. calculate the thermal efficiency ,source and sink temperature

Answer 1

We have two reserviour T₁ and T₃ .

he workout put of the engine is 0.6 times the heart rejected.

A = Q₁ - Q₂ = 0.6Q₁

$\eta = \frac{Q_1-Q_2}{Q_1} = \frac{0.6Q_1}{Q_!} = 0.6$

T₁ - T₂ = 200K

$\eta = \frac{T_1 - T_2}{T_1} = \frac{200}{T_!} = 0.6$ -> T₁ = $\frac{2000}{6}$ = 333K - source temperature

T₂ = T₁ - 200K = 133K - sink temperature