Let`s solve this question:
we need to define K if length of spring is doubled:
"k=E\\times \\frac{S}{l}", E - young modules, S- area of spring and l-length of spring, So if we doubled length:
"k1=E\\times \\frac{S}{2\\times l}"="\\frac{k}{2}", k decreases twice than first vaue.
Potential energy: "E=\\frac{k1\\times l^2}{2}" if we put k and l:
"E(final)=\\frac{\\frac{k}{2}\\times (2\\times l)^2}{2}=2\\times E" this means if doubled length of spring, then its potential energy also doubled.
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