Answer to Question #150353 in Mechanics | Relativity for Jehieli Rosas

Question

A large gun fires a shell with a muzzle velocity of 400m/sec. What is the renge of the gun when it is elevated at an angle of: 30? and 50?

Answer 1

Solution:

Range of object projected at an angle θ

$R=( \dfrac{V^2}{g})sin(2 \theta)$

V is initial velocity in $\tfrac{m}{s}$

g is the acceleration of gravity 9.8 $( \tfrac{m}{s^2})$

$R_1=( \dfrac{400^2}{9.8} )sin(2*30) = 14140m$

$R_2=( \dfrac{400^2}{9.8})sin(2*50)=16080m$