Answer to Question #143119 in Mechanics | Relativity for Mikkos Joshua Garcia

Question #143119
a. A ball is thrown horizontally at 8 m/s. (a) How fast is it moving 2 s later? In what direction is it moving?
b. An airplane is in level flight at a velocity of 300 miles per hour and an altitude of 5000 ft when it drops a bomb. (a) How long does the bomb take to reach the ground? (b) What will the bomb's velocity be on impact?

I need an illustration and complete solution. Thank you
1
Expert's answer
2020-11-12T09:36:37-0500


a) Find the vertical velocity vy=g×t=10×2=20v_y=g\times t = 10\times 2 = 20 m/s.

Then the ball speed will be v=vy2+vx2=202+8221.54v =\sqrt {v _ y ^ 2 + v _ x ^ 2} =\sqrt {20 ^ 2 + 8 ^ 2 }\approx 21.54 m/s.

The angle of the ball trajectory in 2 seconds is at an angle to the horizon equal to arctg20868°\arctg {\frac {20} {8} }\approx 68\degree .



b) Since the distance travelled (where 15241524 meters 5000\approx 5000 feet) is S=g×t22S =\frac {g\times t ^ 2} {2} , therefore t =\sqrt 2×Sg=2×15241017.46{\frac {2\times S} {g}} =\sqrt {\frac {2\times 1524} {10} }\approx17.46 s

Then the vertical velocity is vy=10×17.46=174.6v_y=10\times 17.46 = 174.6 m/s

300300 miles/hours 134.08\approx134.08 m/s.

vtotal=174.62+134.082220.14v_{total}=\sqrt{174.6^2+134.08^2}\approx 220.14 m/s

 



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