A) Since density is "\\rho=\\frac{m}{V}" , then "m=\\rho\\times V=0.8\\times160\\times10^{-6}\\times150" "=1.92\\times 10^{-2}" kg.
B) According to the law of conservation of momentum, the gas pulse is transmitted to the astronaut's pulse "m_g\\times v=\\Delta p_a" , since "F=\\frac{\\Delta p_a}{\\Delta t}=a\\times M", then "a=\\frac{m_g\\times v}{\\Delta t \\times M}= \\frac{1.92\\times 10^{-2}\\times 150}{1 \\times 130}\\approx0.02" m/s"^2" .
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