A) Force of powder charges and barrel length.
B) Since the work is equal to the change in kinetic energy, "F\\times L =\\frac {m\\times v ^ 2} {2}" , where F is the force of powder charges, L is the length of the barrel, m is the mass of the projectile, v is the velocity of the projectile. Since acceleration "a =\\frac {F} {m}" , therefore:
"a =\\frac {v ^ 2} {2\\times L}" , since the flight length "l =\\frac {v ^ 2\\times\\sin {2\\alpha}} {g}" , then
"a =\\frac {g\\times l} {2\\times L\\times\\sin {2\\alpha}}" , therefore the smaller the barrel length the greater the acceleration.
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