Question

A train travels on a straight track passing a signal A at 20m/s. It accelerates uniformly at 2m/s and reaches signal B 100 m further than A. At B the velocity of the train in m/s is?

Answer 1

Initial velocity $u=20m/s$

Acceleration $a= 2m/s^2$

Distance $S= 100m$

Final velocity ( Velocity at pole B) ($v$ ) :

$v^2 = u^2+2aS$

$v^2=20^2+2\times2\times100=800$

$v=28.28m/s$