From the picture we can write that
Tcos15o=mgT\cos 15^o=mgTcos15o=mg ......(1)
Tsin15o=qET\sin15^o=qETsin15o=qE ......(2)
From 1 and 2
tan15o=qEmg\tan 15^o=\frac{qE}{mg}tan15o=mgqE
q=0.27×0.002×10/E=0.0054/Eq=0.27\times0.002\times10/E=0.0054/Eq=0.27×0.002×10/E=0.0054/E
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