An object is initially traveling in the positive x direction with a velocity of +5m/s and an acceleration of +3m/s2. At what position will it be after 8 seconds? (You may assume that it starts at xo = 0).
It is the motion with constant acceleration, so "a=+3\\,\\mathrm{m\/s}^2, \\; v(t) = v_0 + at = +5\\,\\mathrm{m\/s} + 3\\,\\mathrm{m\/s^2}\\cdot t,"
"x(t) = x_0 + v_0t + \\dfrac{at^2}{2} = 0 + 5\\,\\mathrm{m\/s}\\cdot t + \\dfrac{3\\,\\mathrm{m\/s^2}\\cdot t^2}{2}."
Therefore, "x(8) = 0 + 5\\,\\mathrm{m\/s}\\cdot 8\\,\\mathrm{s} + \\dfrac{3\\,\\mathrm{m\/s^2}\\cdot (8\\,\\mathrm{s})^2}{2} = 136\\,\\mathrm{m}."
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