Question #130497
A cube of volume 1 cubic metres and specific gravity 2 is very slowly being lowered in to a lake with help of a massless string tied to one of its vertices A (i.e., body diagonal AB is perpendicular to surface of water).

Initially, the other opposite vertex B is just touching the surface of water and finally, vertex A is just beneath the surface of water. (Ignore change in KE of water). (g= 10ms2).

Find
(a) Work done by gravity on cube.
(b) Work done by gravity on water
(c) Work done by gravity on water + cube system.
(d) Work done by tension on cube.
1
Expert's answer
2020-08-25T11:13:42-0400

a) By the formula of work:

A=PSA=P*S

where P is ponderosity of cube.

Specific gravity: γ=PV>P=γV\gamma=\frac{P}{V}->P=\gamma*V

A=γVSA=\gamma*V*S

S=dS=d, dd is the diagonal of cube. If a=1>d=a3=31.7a=1 ->d=a\sqrt{\smash[b]{3}}=\sqrt{\smash[b]{3}}\approx1.7

A=211.7=3.4A=2*1*1.7=3.4 (J)


b) Work done by gravity of water:

A=FASA=F_A*S

FAF_A is extrude Archimedes force. FA=ρgV=1000101=10000F_A=\rho*g*V=1000*10*1=10000 (N)

A=100001.7=17000A=10000*1.7=17000 (J)


c) Work done by gravity on water + cube system:

A=17000+3.4=17003.4A=17000+3.4=17003.4 (J)


d) Work done by tension on cube:

A=3.4A=3.4 (J)


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