Question #130134

A garden hose attached with a nozzle is used to fill a 10-gal bucket. The inner diameter of the hose is 2 cm, and it reduces to 0.8 cm at the nozzle exit. density of water 1000 kg/m3; 1 gal = 3.789 x 10-3 m3.

If it takes 50 s to fill the bucket with water, determine the volume flow rates of water through the hose, and the average velocity of water at the nozzle exit.

Expert's answer

The time to full the bucket is determined from the volume rate flow and the volume of the bucket:

Δt=VV˙V˙=VΔt\Delta t = \frac{V}{\dot{V}} \Rightarrow \dot{V} = \frac{V}{\Delta t }

V˙=3.78910250=0.7578103(m3s)\dot{V} = \frac{3.789 \cdot 10^{-2}}{50} = 0.7578 \cdot 10^{-3} (\frac{m^3}{s})

The average velocity can be determined from the volume flow rate and cross-sectional area at the nozzle exit:

V˙=Av=πD24vv=4V˙πD2\dot{V} = Av = \frac{\pi D^2}{4}v \Rightarrow v = \frac{4 \dot{V}}{\pi D^2}

v=40.75781033.1415(0.8102)2=15.1(ms)v = \frac{4 \cdot 0.7578 \cdot10^{-3}}{3.1415 \cdot (0.8 \cdot 10^{-2})^2} = 15.1 (\frac{m}{s}).


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