Explanations & Calculations
- To do this sum consider about some volume of water having a mass “m(kg)” hitting the wall at the given velocity “v” and rebounds after a period “t (s)”.
- Due to the change of momentum within this period, a force (F) is exerted on that volume of water (same is exerted on the wall at the point of hit).
- Applying the equation related to momentum change,
F=tmv−mu=tmu−m(−u)=t2mu=2u(tm)
- This tm is called the rate of mass flow which equals to,
=tAxρ=Aρ(tx)=Aρu : ρ= density of water
F=2u×Auρ=2Au2ρ=2×20×10−4m2×(10ms−1)2×103kgm−3=40N
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