The ball has two projections of speed: vx and vy .
At the initial moment:
v0x=v0×cos(α)v0y=v0×sin(α)
The x-projection of speed will not change in time.
The y-projection:
vy=v0y+at=v0y−gt
Take g=10 :
vx=v0x=12×cos(55)≈6.88vy=12×sin(55)−10×2.16≈−11.76
So:
v=vx2+vy2=47.3344+138.2976≈13.63m/s
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