Question #114824
A 1000 kg car traveling @ 30 m/s, 30 degrees S of E collides w/a 3000 kg Truck heading NE @ 20 m/s and makes the collision completely inelastic. Inelastic? Estimate the final dir then find how fast and in what dir they are traveling after the crash.
1
Expert's answer
2020-05-12T09:32:09-0400

Sinse the collision is completely inelastic then applying the law of conservation of momentum we obtained m1v1+m2v2=(m1+m2)vm_1\vec v_1+m_2\vec v_2=(m_1+m_2)\vec v where m1v1m_1\vec v_1 is the momentum of the car , m2v2m_2\vec v_2 is the momentum of the trac, (m1+m2)v(m_1+m_2)\vec v is momentum of the composite body. Than

v=(m12v12+m22v22+2m1m2v1v2cos(v1,v2)m1+m217ms1v= \frac { \sqrt {(m_1^2v_1^2+m_2^2v_2^2+2m_1m_2v_1v_2\cos(\vec v_1,\vec v_2)}}{m_1+m_2}\approx17ms^{-1} ,cos(v,v1)=m1v1+m2v2cos(v1,v2)v(m1+m2)0.21\cos(\vec v,\vec v _1)=\frac{m_1v_1+m_2v_2\cos(\vec v_1,\vec v_2)}{v(m_1+m_2)}\approx0.21

then <(v,v1)780(\vec v,\vec v_1)\approx78^0

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