Question #114824

A 1000 kg car traveling @ 30 m/s, 30 degrees S of E collides w/a 3000 kg Truck heading NE @ 20 m/s and makes the collision completely inelastic. Inelastic? Estimate the final dir then find how fast and in what dir they are traveling after the crash.

Expert's answer

Sinse the collision is completely inelastic then applying the law of conservation of momentum we obtained m1v1+m2v2=(m1+m2)vm_1\vec v_1+m_2\vec v_2=(m_1+m_2)\vec v where m1v1m_1\vec v_1 is the momentum of the car , m2v2m_2\vec v_2 is the momentum of the trac, (m1+m2)v(m_1+m_2)\vec v is momentum of the composite body. Than

v=(m12v12+m22v22+2m1m2v1v2cos(v1,v2)m1+m217ms1v= \frac { \sqrt {(m_1^2v_1^2+m_2^2v_2^2+2m_1m_2v_1v_2\cos(\vec v_1,\vec v_2)}}{m_1+m_2}\approx17ms^{-1} ,cos(v,v1)=m1v1+m2v2cos(v1,v2)v(m1+m2)0.21\cos(\vec v,\vec v _1)=\frac{m_1v_1+m_2v_2\cos(\vec v_1,\vec v_2)}{v(m_1+m_2)}\approx0.21

then <(v,v1)780(\vec v,\vec v_1)\approx78^0

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