Question

A hydraulic press has two pistons, where the diameter of one of them is double that of the other, when the small piston is affected by pressure P, the pressure affects the big piston will be

Answer 1

The Force should be equal for both pistons, so

$P*S=const$

where $P$ - pressure and $S$ - square

$P_1=P$ for small piston

Since $D_2/D_1=2$ , then $S_2/S_1=(D_2/D_1)^2=4$

Then pressure in big piston will be $P_2=P_1S_1/S_2=P/4$