Question #103304
Two objects are connected by a light string that passes over a frictionless pulley. The coefficient of sliding friction between the 4kg object and surface is 0.30. Find the acceleration of the two object and tension in the string, other object is 10kg
1
Expert's answer
2020-02-19T09:42:48-0500



We write the equations of motion for each body in projections on the coordinate axes

на ось x

Ffr+T=m1a-F_{fr}+T=m_1a (1)

на ось y

m2gT=m2am_2g-T=m_2a (2)

m1gN=0m_1g-N=0 (3)

given that Ffr=μNF_{fr}=\mu N from the equation (3) we write Ffr=μm1gF_{fr}=\mu m_1g

add (1) to (2)

m2gFfrT+T=m2a+m1am_2g-F_{fr}-T+T=m_2a+m_1a

or

m2gμm1g=m2a+m1am_2g-\mu m_1g=m_2a+m_1a

g(m2μm1)=(m2+m1)ag(m_2-\mu m_1)=(m_2+m_1)a

Then the acceleration is

a=g(m2μm1)m2+m1=9.81(100.34)10+4=6.166m/s2a=\frac{g(m_2-\mu m_1)}{m_2+m_1}=\frac{9.81(10-0.3 \cdot 4)}{10+4}=6.166 m/s^2

from (2) we determine the string tension

T=m2gm2a=m2(ga)=10(9.816.166)=36.44NT=m_2g-m_2a=m_2(g-a)=10(9 .81-6.166)=36.44 N



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