We write the equations of motion for each body in projections on the coordinate axes
на ось x
"-F_{fr}+T=m_1a" (1)
на ось y
"m_2g-T=m_2a" (2)
"m_1g-N=0" (3)
given that "F_{fr}=\\mu N" from the equation (3) we write "F_{fr}=\\mu m_1g"
add (1) to (2)
"m_2g-F_{fr}-T+T=m_2a+m_1a"
or
"m_2g-\\mu m_1g=m_2a+m_1a"
"g(m_2-\\mu m_1)=(m_2+m_1)a"
Then the acceleration is
"a=\\frac{g(m_2-\\mu m_1)}{m_2+m_1}=\\frac{9.81(10-0.3 \\cdot 4)}{10+4}=6.166 m\/s^2"
from (2) we determine the string tension
"T=m_2g-m_2a=m_2(g-a)=10(9\n.81-6.166)=36.44 N"
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