Answer to Question #103287 in Mechanics | Relativity for Sam

Question

A bullet of mass 55g is shot through a watermelon with mass 1.2kg. the watermelon flies back at 1.5m/s with the bullet inside. what was the bullet’s speed upon entering the watermelon?

Answer 1

From the conservation of momentum:

$mv=(m+M)u$

$(0.055)v=(0.055+1.2)1.5$

$v=34\frac{m}{s}$