Answer to Question #102108 in Mechanics | Relativity for Ibi

Question #102108
Stewart Dent is asked to measure the density of a piece of iron. He measures the mass of the iron and records a value of 97.4g. He measures the volume of water in a graduated cylinder as 50.4mL, after submerging the iron , the volume is 63.3mL .if tje actual density of iron is 7.874g/mL what is Stewart's %-error?
1
Expert's answer
2020-02-03T13:31:27-0500

Calculated value of density:


ρapprox=mV=mV1V0,{\rho}_{approx} = \cfrac m V = \cfrac m {V_1 - V_0} ,

where

m\qquad m - measured mass of the iron

V0\qquad V_0 - volume of water in a graduated cylinder before submerging the iron

V1\qquad V_1 - volume of water in a graduated cylinder after submerging the iron


ρapprox=97.463.350.47.6 (g/mL){\rho}_{approx} = \cfrac {97.4} {63.3 - 50.4} \approx 7.6 \text{ (g/mL)}


Stewart's %-error (relative error):


δ=ρρapproxρ100%=1ρapproxρ100%=17.67.874100%3.5%\delta = \Big| \cfrac {\rho - {{\rho}_{approx}}} \rho \Big| * 100\% = \Big| 1 - \cfrac {{\rho}_{approx}} \rho \Big| * 100\% = \Big| 1 - \cfrac {7.6} {7.874} \Big| * 100\% \approx 3.5\%



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