Question

A simple pendulum has a length of 1.5m and a bob of mass 0.2kg. If the amplitude of oscillation of the bob is 0.05m, calculate period of oscillation

Answer 1

The period of oscillation:

$$T=2\pi \sqrt{\frac{l}{g}}$$

$$T=2\pi \sqrt{\frac{1.5}{9.8}}=2.5\ s$$