Question

Ferd charges an ebonite rod, which always becomes negative, with a charge of 23.7 nC.  The magnetic field in the lab is 4.53E-5 T[North]. Ferd throws with a velocity of 4.8 m/s[West]. What is the resulting magnetic force? Show how you got your answer for both magnitude and direction.

Answer 1

$$F=qBv\\F=(23.7\cdot10^{-9})(4.53\cdot10^{-5})(4.8)\\=5.15\cdot10^{-12}\ N$$

Direction: downwards.