Answer to Question #199096 in Field Theory for Mallory

Question #199096

What potential difference is required to accelerate a proton from rest to a speed of 5.72E7 m/s?




1
Expert's answer
2021-05-30T13:29:25-0400
PE=KE,PE=KE,qΔV=12mv2,q\Delta V=\dfrac{1}{2}mv^2,ΔV=mv22q\Delta V=\dfrac{mv^2}{2q}ΔV=1.671027 kg(5.72107 ms)221.61019 C=1.7107 V.\Delta V=\dfrac{1.67\cdot10^{-27}\ kg\cdot(5.72\cdot10^7\ \dfrac{m}{s})^2}{2\cdot1.6\cdot10^{-19}\ C}=1.7\cdot10^7\ V.

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