solution
work done by centrifugal force can be given as
W=∫r1r2mω2rdrW=\int^{r_2}_{r_1}m\omega^2rdrW=∫r1r2mω2rdr
so
W=12mω2(r22−r12)W=\frac{1}{2}m\omega^2(r_2^2-r_1^2)W=21mω2(r22−r12)
W=12×0.1×52×(0.52−0.32)W=\frac{1}{2}\times0.1\times5^2\times(0.5^2-0.3^2)W=21×0.1×52×(0.52−0.32)
W=0.20JW=0.20JW=0.20J
so work done by centrifugal force is 0.20J.
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