In a rectangular coordinate system, a most of 2×10^-9 kg is a placed at the origin of the coordinates and a most of 25×10^-9 kg is at the point of x=6m and y=0m.
What is the gravitational field at 1.x=3m,y=0m 2.x=3m,y=4m
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Expert's answer
2019-12-10T09:55:30-0500
Assume m1=2×10−9 kg, m2=25×10−9 kg
1) Distances to masses r=r1=r2=3 m
Gravitational field, created by masses:
g1=mF1=r2Gm1,g2=mF2=r2Gm2
As gravitational field is Vector sum of gravitational field gives
g=(g2−g1)ex=r2G(m2−m1)ex
∣g∣=r2G(m2−m1)=1.854∗10−19 ms−2
2) Distances to masses r=r1=r2=32+42 m=5 m
Use a law of cosine to find resulting magnitude:
angle between forces F1 and F2 : α=2arccos54 , cosα=257
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