The magnitude of the electric field, created by a point charge qqq at distance rrr is E=kqr2E = k\frac{q}{r^2}E=kr2q, where k=14πε0=8.85⋅10−12Nm2C−2k = \frac{1}{4 \pi \varepsilon_0} = 8.85 \cdot 10^{-12} N m^2 C^{-2}k=4πε01=8.85⋅10−12Nm2C−2.
Hence, for q=e=1.6⋅10−19Cq = e = 1.6 \cdot 10^{-19}Cq=e=1.6⋅10−19C and r=50cm=0.5mr = 50 cm = 0.5 mr=50cm=0.5m, the magnitude of electric field is E=5.7⋅10−30VmE = 5.7 \cdot 10^{-30} \frac{V}{m}E=5.7⋅10−30mV.
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