Electricity and Magnetism Answers

A small charge (q= 6.0 mC) is found in a uniform E-field (E= 2.9 N/C). determine the force on the charge.

 Find the electric field acting on a 2.0 C charge of an electrostatic force of 10,500 N acts on the particle.

A small charge (q= 6.0 mC) is found in a uniform E-field (E= 2.9 N/C). determine the force on the charge.

Two-point charges are arranged on the x-y coordinate system as follows: q1= 4x10^-8 C at (0,3 m) and q2= -9x10^-7 C at (5,0 m). Find the electric origin at (0,0). Using the Pythagorean theorem calculate for the magnitude E of the resultant electric field.

A conducting sphere of raduis 8.0cm carries o uniform volume charge density of 500 NC/m3. What is the electric field in N/C at r= 3.0cm?

A positive point charge q1 at the origin and a negative charge q2 at x=2m. The resultant electric field is 10.8 i N/C at x=1m and -8 i N/C at x=3m. Find q1 and q2.

An electron penetrates the region between two uniformly charged horizontal plates, but oppositely signed. Its initial speed, at half distance between the plates is 2×10 ^6 i m/s. The plates have a length of 4 cm and are 1.6 cm apart. In the whole region between the plates, the electric field ́ is uniform and perpendicular to the plates. (a) what is the maximum modulus that the vertical electric field can have so that the electron does not touch any plate?

The answer is 228 N/C but I'm not too sure how they got that?

A point particle of charge 2.5 nC and mass 3.25 x10-^3 is in uniform electric field directed to the right .It is released from rest and moves to the right .After it is travel ed 12.0 cm,it's speed us 25m/s.Find the

a) qork done on the particle

b)change un the electric potential energy of the particle

c) magnitude of the electric field.

compute the force of attraction between a. +1.60 × 10-19 c charge and a -2.09 × 10-18 c charge if they are 4.01 × 10-10m apart

Which is a more precise measuring tool : ruler or Vernier Caliper? Why?