Question #298349

Two-point charges are arranged on the x-y coordinate system as follows: q1= 4x10^-8 C at (0,3 m) and q2= -9x10^-7 C at (5,0 m). Find the electric origin at (0,0). Using the Pythagorean theorem calculate for the magnitude E of the resultant electric field.


1
Expert's answer
2022-02-16T08:36:06-0500

Answer

Electric field at origin due to q1

E1=kq1r2=9109410832=40N/CE_1=\frac{kq_1}{r^2}\\=\frac{9*10^9*4*10^{-8}}{3^2}\\=40N/C

Electric field at origin due to q2

E2=kq2r2=9109910752=324N/CE_2=\frac{kq_2}{r^2}\\=\frac{9*10^9*9*10^{-7}}{5^2}\\=324N/C

So net electric field at origin is E=E12+E22=(40)2+(324)2=326.46N/CE=\sqrt{E_1^2+E_2^2}\\=\sqrt{(40)^2+(324)^2}\\=326.46N/C






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