Answer to Question #96170 in Electricity and Magnetism for Kachi

Question

charges of 3nC, -2nC, -7nC and 1nC are contained inside a rectangular box with length 1m width 2m and height 2.5m. Outside the boc are charges of 1nC and 4nC. What os the electric flux through the sirface.

Answer 1

The total of the electric flux for a closed surface is equal to the total charge divided by the permittivity.

In our case the total charge Q=Q_inside-Q_outside=(3nC-2nC-7nC+1nC)-(1nC+4nC)=-10nC

Total flux F=Q/e₀=-10nC/(8.85*10^-12F/m)=-1.13*10³V*m