The emf induced in the coil of electrical generator is given by formula
The amplitude of emf
"{\\mathcal E_m}=NAB\\omega"
Therefore
Finally
"{\\omega_2}=\\frac{\\mathcal E_{m2}}{{\\mathcal E_{m1}}}{\\omega_1}"
"{\\omega_2}=\\frac{8\\:\\rm V}{10\\:\\rm V}\\times{5\\:\\rm rad\/s}=4\\:\\rm rad\/s"
Comments
Leave a comment