Question #95511

the initial angular speed of the coil in the generator is 5 rad/s and the initial amplitude of the induced emf is 10 v.calculate the angular speed of the coil in the generator when the amplitude of the induced emf is 8v

Expert's answer

The emf induced in the coil of electrical generator is given by formula


E=NABωsin⁡ωt{\mathcal E}=NAB\omega\sin\omega t

The amplitude of emf

Em=NABω{\mathcal E_m}=NAB\omega

Therefore


Em2Em1=ω2ω1\frac{\mathcal E_{m2}}{{\mathcal E_{m1}}}=\frac{\omega_2}{\omega_1}

Finally

ω2=Em2Em1ω1{\omega_2}=\frac{\mathcal E_{m2}}{{\mathcal E_{m1}}}{\omega_1}

ω2=8 V10 V×5 rad/s=4 rad/s{\omega_2}=\frac{8\:\rm V}{10\:\rm V}\times{5\:\rm rad/s}=4\:\rm rad/s


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