Question

In the figure particle 1 of charge q1 = 0.92 μC and particle 2 of charge q2 = -2.99 μC, are held at separation L = 10.9 cm on an x axis. If particle 3 of unknown charge q3 is to be located such that the net electrostatic force on it from particles 1 and 2 is zero, what must be the (a)x and (b)y coordinates of particle 3?

Answer 1

a)

$$E_1=E_2$$

$$k\frac{q_2}{(L+x)^2}=k\frac{q_1}{( x)^2}$$

$$\frac{2.99}{(10.9+x)^2}=\frac{0.92}{( x)^2}$$

$$x=13.6\ cm$$

b) Any value.