4 point charge of +Q each are located at corners of square, what point charge to be kept at center of the square so that the resulted force acting on any charge which are located at the corners of square is 0?
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Expert's answer
2019-07-12T09:10:20-0400
Consider 5 charges: Q in the points (l,0), (0,l), (-l, 0), (0, -l) and q in (0,0) The force between two charges q1 and q2 is given by
F=r3kq1q2r
where r is the distance between them. Due to the symmetry it is sufficient to consider only one charge, for example the one in the point (l,0). We have 4 forces acting on it:
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