First, write Faraday's law:
What changes here is the area if the coil, thus
"emf=NB\\space\\text{cos}\\space\\theta\\space\\frac{dA}{dt}=\\\\\n=200\\cdot50\\cdot10^{-6}\\cdot\\text{cos}\\space28^\\circ\\frac{39\\cdot10^{-4}}{1.80}=19.13\\cdot10^{-6}\\text{ V}."
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