Question #83008

A heat pump is used to meet the heating requirements of a house and
maintain it at 20°C. On a day when the outdoor air temperature drops to
-2°C, the house is estimated to lose heat at a rate of 80,000 kJ/h. If the
heat pump under these conditions has a COP of 2.5, determine (a) the
power consumed by the heat pump and (b) the rate at which heat is
absorbed from th

Expert's answer

Answer on Question # 83008, Physics / Electromagnetism

Question 1. A heat pump is used to meet the heating requirements of a house and maintain it at 20C20{}^{\circ}C. On a day when the outdoor air temperature drops to 2C-2{}^{\circ}C, the house is estimated to lose heat at a rate of 80000kJ/h80000\,kJ/h. If the heat pump under these conditions has a COP of 2.52.5, determine

(a) the power consumed by the heat pump and

(b) the rate at which heat is absorbed from th

Proof. COP=QconsumerWCOP=\dfrac{Q_{\rm consumer}}{W}, where QconsumerQ_{\rm consumer} is a heat received by the consumer and WW is pump work.

Qconsumer=80000kJQ_{\rm consumer}=80000\,kJ because if we lose 80000kJ/h80000\,kJ/h, then we must replenish 80000kJ/h80000\,kJ/h to maintain the temperature.

So the power is P=ΔW/Δt=W=QconsumerCOP=32000kJ/h=32000000/3600J/s8888.888888889W.P=\Delta W/\Delta t=W=\dfrac{Q_{\rm consumer}}{COP}=32000\,kJ/h=32000000/3600\,J/s\approx 8888.888888889\,W.

And the rate at which heat is absorbed from the outdoor is 80000kJ/h80000\,kJ/h. \Box

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