Answer to Question #76011 in Electricity and Magnetism for Deepesh Tripathi

Question

In an induction coil , the coefficient of mutual inductance is 4 Henry . if a current of 5 ampere in the primary coil is cut off in 1/1500 sec , the emf at the terminals of the secondary coil will be (1) 15kV. (2) 60 kV (3) 10 kV. (4) 30 kV

Answer 1

The emf at the terminals of the secondary coil will be
E=L ΔI/Δt
E=4 5/(1/1500)=30000 V=30 kV