Question #76011

In an induction coil , the coefficient of mutual inductance is 4 Henry . if a current of 5 ampere in the primary coil is cut off in 1/1500 sec , the emf at the terminals of the secondary coil will be (1) 15kV. (2) 60 kV (3) 10 kV. (4) 30 kV

Expert's answer

The emf at the terminals of the secondary coil will be
E=L ΔI/Δt
E=4 5/(1/1500)=30000 V=30 kV

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Canada #340153 on Dec 2023