Answer to Question #315968 in Electricity and Magnetism for Lhen

Question

A -6 nC particle is moving at 4.0x10^4m/s along the positive z-axis.It passes a region undeflected where there is uniform electric and magnetic fields.The electric field is 5.75 x10^5 N/C along the negative x-axis.What is the magnitude and direction of the magnetic field.

Answer 1

We know that

$qE=q(V\times B)$

$E=(V\times B)$

$E=VB sin\theta$

$B=\frac{E}{V}$

$$B=\frac{5.75\times10^5}{4\times10^4}=14.375T$$

Direction of magnetic field

+ y direction