Question

An electron is placed in an electric potential of 1nV. Determine the velocity of the electron after passing through the potential assuming it was motionless in the beginning

Answer 1

We know that

$\frac{1}{2}mv^2=eV$

$v=\sqrt{\frac{2eV}{m}}$

$$v=\sqrt{\frac{2\times1.6\times10^{-19}\times10^{-9}}{9.1\times10^{-31}}}=18.75m/sec$$